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160 Triple Integration & its Applications Chapter -6
6
Triple Integration & its Applications
1. TRIPLE INTEGRATION
In the preceeding sections we defined and discussed the properties of single and double integrals for functions
of single variable and two variables respectively. In this section, we will define triple integrals for functions of
three variables.
• The triple integral of f (x, y,z) is denoted by f (x, y,z)dV and is defined as
D
g2(x, y)
f (x, y,z)dV f (x, y,z)dzdA where D is a simply xy-solid with upper surface z g (x, y)
2
D R g (x, y)
1
and lower surface z g (x, y), and let R be the projection of D on the xy-plane.
1
• If D is a rectangular box defined by the inequalities a x b, c y d, k z l , then
b d l
f (x, y,z)dV f (x, y, z)dzdydx
D a c k
Volume element
dV dzdydx dzdxdy dxdydz dxdzdy z
z
dydxdz dydzdx k y
Cuboidal x
V (x)(y)(z) sub-region
V x
k k
yk
Evaluating Triple Integrals :
Step 1.Find an equation z g (x, y) for the upper surface and an equation z g (x, y) for the lower surface of G.
2 1
The functions g (x, y) and g (x, y)determine the lower and upper z-limits of integration.
1 2
Step 2.Make a two-dimensional sketch of the projection R of the solid on the xy-plane. From this sketch determine
the limits of integration for the double integral over R.
Step 3.After finding limits of integration, do the integration as in case of double integral i.e., partial integration.
Geometric Interpretation:
From the definition of the triple integral
dV volume of the region D.
D
Chapter-6 Triple Integration & its Applications 161
1 2 3
Ex.1: Evaluate : xyzdzdxdy
0 0 0
Soln. Here limit of z : 0 z 3
Here limit of x : 0 x 2
Here limit of y : 0 y 1
1 2 3 1 2 1
zdzxdx ydy 9xdx ydy 36 ydy 36
2 4 8
0 0 0 0 0 0
1 1 2
Ex.2: Evalute x2z2ydzdxdy
1 0 1
1 1 2 1 1 2 1 7
Soln. x2z2ydzdxdy ydy x2dx z2dz 0 0
3 3
1 0 1 1 0 1
1/2 1
Ex.3: Evalute zxsinxydzdydx
1/3 0 0
1/2 1 1/2 1
zxsinxydzdydx zdzxsin(xy)dydx
Soln.
1/3 0 0 1/3 0 0
1/2 1/2
1xsin(xy)dydx 1 sin(xy)dyxdx
2 2
1/3 0 1/3 0
11/2 cosxy 11/2 1 sinx 1/2
xdx (1cosx)dxss x
2 x 2 2
0
1/3 1/3 1/3
sin sin
11 2 1 3 1 1 1 1 1 1 1 1 1 1
2 2 3 26 2 26 2 43
/4 1 x2
Ex.4: Evalute xcosydzdxdy
0 0 0
/4 1 x2 /4 1 /4 1
xcosydzdxdy [z]x2xcos ydxdy x3cosydxdy
Soln. 0
0 0 0 0 0 0 0
/4 1 1 1 1
cosydy x3dx
2 4 4 2
0 0
Ex.5: Evaluate ydV,where G is the solid enclosed by the plane z = y, the xy-plane, and the parabolic cylinder y
G
2
= 1 – x .
Soln. Limit of z, 0 z y
Limit of y, 0 y 1 x2
162 Triple Integration & its Applications Chapter -6
Limit of x, 1 x 1 y
y
ydv ydzdxdy
G R 0 R
1 1x2 1 1 x
y2dydx (1 x2)3dx
3
1 0 1
2 1 2 1 3 32
(1 x6 3x4 3x2)dx 1 1
3 3 7 5 70
1
9 3 x z
Ex.6: Change the order of the integral f (x, y,z)dydzdx
0 0 0
Soln. Limit of x, 0 y z z
Limit of y, 0 z 3 x 3
Limit of z, 0 x 9
i.e., Region bounded by y = z, z 3 x, 0 9 x
xz-plane, yz-plane
9 3 x z 3 (3z)2 z
f (x, y,z)dydzdx f (x, y,z)dydzdx y
0 0 0 0 0 0 3 y 3 x
9 3 x 3 x
f (x, y,z)dzdydx
0 0 y 0 9 x
3 (y3)2 3 x
f (x, y,z)dzdydx
0 0 y
• To change the order of integral First we consider
(i) region of integral
(ii) Go parallel to axis suppose we first consider limit of z then we go parallel to z-axis. Put lower limit entering
first surface in x, y relation and put upper limit ending with surface in x, y relation.
(iii) Then we find out the relation in x and y with the help of z
(iv) Now we work just as double integral
1.1 Cylindrical coordinates
Cylindrical coordinates of a point P is (r,, z) as shown in the figure. If cartesian coordinates of P be
(x, y, z) then
z
x rcos, y rsin,z z P(r, , z)
r2 x2 y2 and tan y / x z
O y
For one-to-one correspondence from rectangular to x r
x
cylindrical coordinates we take r 0 and 02. y P
x
Chapter-6 Triple Integration & its Applications 163
Although, there can be six order of integration, similar to the rectangular coordinates. We take only
rdzdrd as it gives easier integration.
Simple geometries in cylindrical coordinates: z
1. r r (a positive constant)
0
geometry: a right circular cylinder with z-axis its axis and radius as r . y
0 r=r
x 0
z
2. (0 2) (a constant)
0 0
geometry : a plane containing z-axis
and making an angle 0 with positive x-axis. O y
0
x = 0
3. z z (a constant) z
0
geometry: a plane perpendicular to the z
0
z-axis and cutting z-axis at (0, 0, z ) y
0 O
Volume element: Cartesian and cylindrical x
Cartesian Cylindrical
z rd
y z
dz x dz
dx
dy d dr
r
dV dxdydz dV (rd)(dr)dz rdzdrd dzrdrd
(Cuboid) (Cylindrical wedge) z
Integration: For the region, G enclosed by z g2(r,)
z = g (r, )
and z g (r,) and having projection R in the xy-plane 2
1 G
g2(r,) z = g (r, )
1
g(r,,z)rdz drd
g(r,,z)rdzdrd
R g (r,) y
G 1
G : transformed region in coordinate system. x R
r z
Transformation to cylindrical coordinates: Transformation from rectangular to cylindrical coordinates.
f (x, y, z)dzdxdy f (r cos,rsin,z)rdzdrd
D G
G : transformed region in r,,z coordinates
/2cosr2
Ex.7: Evalute rsindzdrd
0 0 0
/2cosr2 /2cos
r2
rsindzdrd [z] rsindrd
Soln. 0
0 0 0 0 0
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